Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mathrm{B}}_2$ and ${\mathrm{O}}_2$ are paramagnetic due to presence of unpaired electron. MO electronic configuration of ${\mathrm{B}}_2$ is: $$\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^1=\pi 2p_y^1$$ MO electorn i.e. configuration of ${\mathrm{O}}_2$ is: $$\begin{array}{l}\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2\\ =\pi 2p_y^2\pi \ast 2p_x^1=\pi \ast 2p_y^1\end{array}$$