Chemistry - CHEMICAL BONDING Question with Solution | TestHub

In${\mathrm{XeOF}}_2$, the central atom has$3$bond pairs and$2$lone pairs. Hence, the electrons will enter a trigonal bipyramidal geometry. The$2$lone pairs will take up equatorial positions giving the molecule a T-shape.$\mathrm{Xe}$in${\mathrm{XeOF}}_4$has$5$bond pairs and$1$lone pair. The electrons will take up square bipyramidal geometry, but due to a lone pair, the shape of the molecule will be square pyramidal.