CHEM_REMOVED - CHEMICAL BONDING Question with Solution | TestHub

The electronic configuration of${\mathrm{H}}_2^{2\ominus }$is$\Rightarrow \left(\mathrm{\sigma }1{\mathrm{s}}^2\right),\mathrm{ }{\left({\mathrm{\sigma }}^{\mathrm{*}}1\mathrm{s}\right)}^2$



Bond order of${\mathrm{H}}_2^{2⊝}=\frac{{\mathrm{N}}_{\mathrm{b}}-{\mathrm{N}}_{\mathrm{a}}}{2}=\frac{2-2}{2}=0$

Hence,${\mathrm{H}}_2^{2\ominus }$does not exist, due to zero bond order.