A m o n g H 2 , H e 2 + , L i 2 , B e 2 , B 2 , C 2 , N 2 , O 2 - , a n d F 2 , the number of diamagnetic species is - (Atomic number : H = 1 , H e = 2 , L i = 3 , B e = 4 , B = 5 , C = 6 , N = 7 , O

Question

A m o n g H 2 , H e 2 + , L i 2 , B e 2 , B 2 , C 2 , N 2 , O 2 - , a n d F 2 , the number of diamagnetic species is - (Atomic number : H = 1 , H e = 2 , L i = 3 , B e = 4 , B = 5 , C = 6 , N = 7 , O = 8 , F = 9 )

TestHub · Accepted Answer

H 2 ⇒ σ 1 s 2 (Diamagnetic) H e 2 + ⇒ σ 1 s 2 σ * 1 s 1 (Paramagnetic) L i 2 ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 (Diamagnetic) B e 2 ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 (Does not exist) B 2 ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 π 2 p x 1 = π 2 p y 1 (Paramagnetic) C 2 ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 π 2 p x 2 = π 2 p y 2 (Diamagnetic) N 2 ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 π 2 p x 2 = π 2 p y 2 σ 2 p z 2 (Diamagnetic) O 2 Θ ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 σ 2 p z 2 π 2 p x 2 = π 2 p y 2 π * 2 p x 2 = π * 2 p y 1 (Paramagnetic) F 2 ⇒ σ 1 s 2 σ * 1 s 2 σ 2 s 2 σ * 2 s 2 σ 2 o z 2 π 2 p x 2 = π 2 p y 2 π * 2 p x 2 = π * 2 p y 2 (Diamagnetic)

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Doubts & Discussion

$H_{2} \Rightarrow σ 1 s^{2}$	(Diamagnetic)
$H e_{2}^{+} \Rightarrow σ 1 s^{2}$ $σ^{*} 1 s^{1}$	(Paramagnetic)
$L i_{2} \Rightarrow σ 1 s^{2} σ^{*} 1 s^{2} σ 2 s^{2}$	(Diamagnetic)
$B e_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2}$	(Does not exist)
$B_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{1} = π 2 p_{y}^{1}$	(Paramagnetic)
$C_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2}$	(Diamagnetic)
$N_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} σ 2 p_{z}^{2}$	(Diamagnetic)
$O_{2}^{Θ} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 p_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{1}$	(Paramagnetic)
$F_{2} \Rightarrow σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} σ 2 o_{z}^{2} π 2 p_{x}^{2} = π 2 p_{y}^{2} π^{} 2 p_{x}^{2} = π^{} 2 p_{y}^{2}$	(Diamagnetic)