CHEM_REMOVED - CHEMICAL BONDING Question with Solution | TestHub

(i)$\begin{array}{ccc}{\text{H}}_2^{2+}& \Rightarrow & \text{B}\text{.}\text{O}=0\\ {\text{He}}_2& \Rightarrow & \text{B}\text{.}\text{O}=\frac{2-2}{2}=0\end{array}\}$

(ii) $\begin{array}{ccc}{\text{H}}_2^{-}& \Rightarrow & \text{B}\text{.}\text{O}=\frac{2-1}{2}=0\text{.}5\\ {\text{He}}_2^{\mathrm{2+}}& \Rightarrow & \text{B}\text{.}\text{O}=1\end{array}$

(iii)$\begin{array}{ccc}{\text{H}}_2^{+}& =& \text{B}\text{.}\text{O}=\frac{1-0}{2}=0\text{.}5\\ {\text{He}}_2^{2-}& =& \text{B}\text{.}\text{O}=\frac{4-2}{2}=1\text{.}0\end{array}$

(iv)$\begin{array}{ccc}{\text{H}}_2^{-}& \Rightarrow & \text{B}\text{.}\text{O}=\frac{2-1}{2}=0\text{.}5\\ {\text{He}}_2^{2-}& \Rightarrow & \text{B}\text{.}\text{O}=\frac{4-2}{2}=1\text{.}0\end{array}$


As both H₂²⁺and He₂have zero bond order and hence do not exist.