Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Electronic configuration of ${\mathrm{O}}_2$ $\begin{array}{rl}& \sigma (1s{)}^2{\sigma }^{\ast }(1s{)}^2\sigma (2s{)}^2{\sigma }^{\ast }(2s{)}^2\sigma {\left(2p_z\right)}^2\pi {\left(2p_x\right)}^2=\pi {\left(2p_y\right)}^2\\ & {\pi }^{\ast }{\left(2p_x\right)}^1={\pi }^{\ast }{\left(2p_y\right)}^1\end{array}$ Thus, the incoming electron will enter in ${\pi }^{\ast }2p_x$ to form ${\mathrm{O}}_2$.