In hypothetical N₂, suppress s–p mixing so σ 2 p , g

Question

In hypothetical N₂, suppress s–p mixing so σ 2 p , g <π 2 p , u <π* 2 p , g <σ* 2 p , u . Then add two electrons sequentially, following Hund's rule. Separately, imagine forcing the two π* electrons of the final dianion into the SAME component while all other occupancies remain fixed. Which statements are correct?

TestHub · Accepted Answer

Neutral N₂ has 10 valence electrons and BO3. Both additions occupy antibonding π* orbitals, reducing BO to2.5 then2. Hund's rule distributes the two π* electrons singly with parallel spins. Pairing them changes spin and energy, not the number of antibonding electrons, so C is false. Both π* components are g, giving D even in the forced-pair excited arrangement.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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