Chemistry - CHEMICAL BONDING Question with Solution | TestHub

In ${\mathrm{OF}}_2$ repulsion between lone pairs is greater than that between bond pair since electrons are away from $\mathrm{O}$ and nearer to $\mathrm{F}$. In ${\mathrm{Cl}}_2\mathrm{O}$, bonding electrons are nearer to $\mathrm{O}$ than to $\mathrm{Cl}$, so the bond angle is greater than $109^{\circ }28^{\prime }$. $\mathrm{In}{\mathrm{Br}}_2\mathrm{O}$, the bonding electrons are more closer to oxygen than in ${\mathrm{Cl}}_2\mathrm{O}$, so the bond angle is largest $\left(116^{\circ }\right)$.