Consider the following statements - (i) NF 3

Question

Consider the following statements -

(i) $NF_{3} < NCl_{3} < CCl_{4} < BeCl_{2}$ : (Bond angle)

(ii) $O - O < S - S < Se - Se < Te - Te :$ (Bond Energy)

(iii) (Staggered form of $B_{2} C ℓ_{4}) = ($ Bridge dimeric $Be_{2} C ℓ_{4})$ : (Maximum number of $C ℓ$ atoms in a plane)

(iv) $PbCl_{2} > PbBr_{2} > PbI_{2}$ : (Solubility in water)

(v) $AlF_{3 (s)} > AlCl_{3 (s)} > AlBr_{3 (s)} > AlI_{3 (s)}$ : (Covalent character)

Select the appropriate option(s).

TestHub · Accepted Answer

(i) Bond angles: NF₃ (102.5°) < NCl₃ (107°) < CCl₄ (109.5°) < BeCl₂ (180°). This order is correct.

(ii) Bond energy: O-O (146 kJ/mol) < S-S (226 kJ/mol) > Se-Se (172 kJ/mol) > Te-Te (126 kJ/mol). This order is incorrect.

(iii) In B₂Cl₄ (staggered), 6 atoms (2B, 4Cl) are in a plane. In Be₂Cl₄ (dimeric), 4 atoms (2Be, 2Cl) are in a plane. So, the statement is incorrect.

(iv) Solubility in water: PbCl₂ > PbBr₂ > PbI₂. This order is correct due to decreasing lattice energy and increasing covalent character down the group.

(v) Covalent character: AlF₃ < AlCl₃ < AlBr₃ < AlI₃ (Fajans' rules). This order is incorrect.

Therefore, statements (i) and (iv) are correct. Statements (ii), (iii), and (v) are incorrect.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:(select one or more)

Doubts & Discussion

JEE Advanced (2027)