Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Bond length $\alpha \frac{1}{\text{ bond order }}$ Bond order $=\frac{\text{ no..of bonding }\overline{\mathrm{e}}-\text{ no.of antibonding }\overline{\mathrm{e}}}{2}$ Bond orders of ${\mathrm{O}}_2^{+},{\mathrm{O}}_2^{-},{\mathrm{O}}_2^{-2}$ and ${\mathrm{O}}_2^{+2}$ are respectively $2.5,1.5,1$ and 3 .