The final product of the reaction

Question

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Step 1: Hoffmann Bromamide Degradation

The reaction of a primary amide with $N a OB r$ (sodium hypobromite) is the Hoffmann bromamide degradation. This reaction converts the amide group ( $CON H_{2}$ ) into a primary amine ( $N H_{2}$ ) by removing the carbonyl carbon. The intermediate product before heating would be the amino acid corresponding to option (C).

$RCON H_{2} + N a OB r RN H_{2} + N a_{2} C O_{3} + N a B r + H_{2} O$

Step 2: Cyclization (Lactam Formation)

Heating ( $Δ$ ) the resulting amino acid (option C) promotes an intramolecular reaction between the amine group and the carboxylic acid group. This leads to the formation of a stable five-membered cyclic amide, known as a lactam (option D), with the elimination of a water molecule.

Answer:

The final product of the reaction is the cyclic lactam shown in option (D).

Chemistry - Carboxylic acid and their Derivatives Question with Solution | TestHub

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