Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureBohr's Atomic ModelHard2 minQB

ChemistryHardsingle choice

For the $He^{+}$ ion, the energy difference between the states $n = 2$ and $n = 3$ is E eV. The ionisation potential of $Li^{2 +}$ is -

Answer:

Solution:

$E = 13.6 \times Z^{2} (1/4 - 1/9) = 13.6 \times 4 \times 5/36 = 7.56$ eV for $He^{+}$ .

I.P. of $Li^{2 +} = 13.6 \times 3^{2} = 122.4$ eV.

$122.4/7.56 = 16.2$ , so I.P. = 16.2 E.

Traps: forgetting $Z^{2}$ in either step gives 8.1 E or 5.4 E.

Answer: (A).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Bohr's Atomic Model

⏱ 2mℹ️ Source: QB

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