Chemistry - Atomic Structure Question with Solution | TestHub

Balmer series starts from$\text{n}=2$. So first emission line in atomic spectrum of$\text{H}$is$\text{2}\to \text{3}$
$\frac{\text{1}}{\text{λ}}\text{=}{\text{RZ}}^{\text{2}}\left[\frac{\text{1}}{{\text{n}}_{\text{1}}^{\text{2}}}\frac{-\text{1}}{{\text{n}}_{\text{2}}^{\text{2}}}\right]$
$\stackrel{-}{\mathrm{\nu }}=\mathrm{R}\left[\frac{1}{2^2}-\frac{1}{3^2}\right]{\mathrm{c}\mathrm{m}}^{-1}=\frac{5\mathrm{R}}{36}\mathrm{c}{\mathrm{m}}^{-1}$