Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The atomic structure of $H e^{+}$ arises due to transition from $n_{2}$ to $n_{1}$ level. If $n_{1} + n_{2}$ is 3 and $n_{2} - n_{1}$ is 1. Find the $λ$ in nm of transition for this series in $H e^{+}$ in nm.

Answer:

30.00

Solution:

$n_{1} + n_{2} = 3$ …(i)
$n_{2} - n_{1} = 1$ …(ii)
$2 n_{2} = 4$
So $n_{2} = 2$
Putting the value of $n_{2}$ in (i) $n_{1} = 3 - n_{2} = 3 - 2 = 1$
$\frac{1}{λ} = R z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) = R . 2^{2} (\frac{1}{1^{2}} - \frac{1}{2^{2}})$
$λ = \frac{1}{3 R} = \frac{1}{3 \times 109678 c m^{- 1}}$
$= 3 \times 1 0^{- 6} c m = 3 \times 1 0^{- 6} \times 1 0^{7} = 30$ nm.

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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