Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureQuantum NumbersMedium2 minQB

ChemistryMediumsingle choice

Maximum value of $n + ℓ + m$ for the last unpaired electron in an element present in $1 7^{th}$ group and $4^{th}$ period in periodic table

Answer:

Solution:

$n = 4$ , $n + 1$ for p subshell, $m = + 1$ .

Thus, $m = 4 + 1 + 1 = 6$ .

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Quantum Numbers

⏱ 2mℹ️ Source: QB

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