Chemistry - Atomic Structure Question with Solution | TestHub

$KE=+13.6\times \frac{Z^2}{n^2}$ (A) ${\mathrm{KE}}_{1,11}=+13.6\times \frac{1^2}{1^2}=13.6\mathrm{eV}$ (B) ${\mathrm{KE}}_{1,\mathrm{Hc}}=+13.6\times \frac{2^2}{1^2}=13.6\times 4\mathrm{eV}$ (C) ${\mathrm{KE}}_{2,{\mathrm{He}}^{+}}=+13.6\times \frac{2^2}{2^2}=13.6\mathrm{eV}$ (D) ${\mathrm{KE}}_{2,\mathrm{Li}}{}^{{\mathrm{i}}^{+}}=+13.6\times \frac{3^2}{2^2}=13.6\times \frac{9}{4}\mathrm{eV}$