Calculate the wavelength of light required to break the bond between two bromine atoms in a bromine molecule. The Br − Br bond energy is 193 kJ / mol .

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ε Br − Br ​ = 6.022 × 1 0 23 193 × 1 0 3 ​ J / Bond ​ = 3.2 × 1 0 − 19 J / Bond ​ = 2 e V / Bond ​ ∴ λ hc ​ = 2 e V ⇒ λ = 2 eV 1240 eV . nm ​ = 620 nm = 6.2 × 1 0 − 7 m Ans.

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