Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSpectrumMedium2 minQB
ChemistryMediummultiple choice

In a hydrogen like sample two different types of photons A and B are produced by electronic transition. Photon has it's wavelength in infrared region if photon A has more energy than B, then the photon A may belong to the region

Options:(select one or more)

Answer:
A, B, C
Solution:

Explain Question:

Identifying spectral regions based on photon energy.

Concept:

Hydrogen Spectrum and Energy Levels.

Solution:

In a hydrogen-like atom, energy levels are grouped into series (Lyman, Balmer, Paschen, etc.). The energy of a photon depends on the gap between these levels. If photon B is in the infrared region, photon A (which has more energy) could be in a higher energy region like visible or ultraviolet.

Calculation:

Energy (E) is inversely proportional to wavelength (λ). The order of regions by increasing energy is:

Infrared < Visible < Ultraviolet. Since Energy of A > Energy of B (Infrared), A could be in the Infrared, Visible, or Ultraviolet region. Among the given choices, both 1, 2, and 3 are physically possible, but in standard multiple-choice contexts for "may belong," we recognize that any region with higher energy than IR is a valid answer.

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Spectrum
2mℹ️ Source: QB

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