Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSpectrumMedium2 minPYQ_2013

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The wave number of the first emission line in the Balmer series of $H$ -Spectrum is : $(R =$ Rydberg constant $)$ :

Answer:

Solution:

$\overset{v}{ˉ} = RZ^{2} (\frac{1}{2 ^{2}} - \frac{1}{3 ^{2}})$ $= R (\frac{1}{4} - \frac{1}{9}) = \frac{5 R}{36}$

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Spectrum

⏱ 2mℹ️ Source: PYQ_2013

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