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Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureRutherford's Atomic ModelMedium2 minQB

ChemistryMediumsingle choice

An α-particle projected with kinetic energy K towards a Cu nucleus $(Z = 29)$ has a distance of closest approach d. A proton with the same kinetic energy K projected towards an Au nucleus $(Z = 79)$ has a distance of closest approach :-

Options:

Answer:

Solution:

$r_{0} = qZ e / (4 π ε_{0} K)$ is proportional to qZ.

α on Cu: $2 \times 29 = 58$ . Proton on Au: $1 \times 79 = 79$ .

$r_{0} = d \times 79/58 = 1.36$ d.

Answer: (A).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Rutherford's Atomic Model

⏱ 2mℹ️ Source: QB

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