Chemistry - Atomic Structure Question with Solution | TestHub

We know that${\text{E}}_{\text{n}}\text{=}{\text{E}}_{\text{1}}\text{×}{\left(\frac{\text{Z}}{\text{n}}\right)}^{\text{2}}$
Given${\text{E}}_{\text{2}}\text{=}\frac{{\text{E}}_{\text{1}}}{{\text{2}}^{\text{2}}}\text{=}-{\text{328 kJ mol}}^{-\text{1}}$
${\text{E}}_{\text{4}}\text{=}\frac{{\text{E}}_{\text{2}}}{{\text{2}}^{\text{2}}}\text{=}\frac{-\text{328}}{\text{4}}{\text{kJ mol}}^{-\text{1}}\text{=}-{\text{82 kJ mol}}^{-\text{1}}$