Chemistry - Atomic Structure Question with Solution | TestHub

A point or plane of an orbital where the electron density of the electron of an orbital is zero is called a node. Nodes can be two types; one is a radial node and another one is an angular node.

Number of radial node$=\mathrm{n}-\mathrm{l}-1$

Now, for $3\mathrm{p}$ orbital, the value of $\mathrm{n}$ is $3$, and the azimuthal quantum number is $1$. Therefore, the number of radial node is, $\mathrm{n}-\mathrm{l}-1=(3-1-1)=1$

Hence, ans will be $\mathrm{A}$