Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSpectrumMedium2 minPYQ_2017

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The electron in the hydrogen atom undergoes transition from higher orbitals to orbital of radius $211.6 pm$ . This transition is associated with

Answer:

Solution:

$R = 211 .6 pm = 2 .11 Å$ .

$R = 0 .529 \times \frac{n^{2}}{Z} = 2 .11 Å .$

$n^{2} = 4 \Rightarrow n = 2$ .

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Spectrum

⏱ 2mℹ️ Source: PYQ_2017

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