Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSpectrumHard2 minQB
ChemistryHardmatching list

Match each transition in Column I with the statements in Column II that are true for the emitted photon of eV; R is the Rydberg constant) (a Column I entry may match more than one Column II entry):

Column I (Transition)

Column II (Statement)

(P) H: to

(1) belongs to the series with

(Q) H: to

(2) belongs to the series with

(R) to

(3) photon energy = 10.2 eV

(S) to

(4) photon energy = 12.75 eV

 

(5) wave number = 3R

 

(6) photon energy = 1.89 eV

Choose the option with the correct matching:

Options:

Answer:
C
Solution:

eV.

(P) 13.6(1/4 - 1/9) = 1.89 eV (6), (1).

(Q) 13.6(1 - 1/16) = 12.75 eV (4), (2).

(R) eV, (2); wave number = (5).

(S) eV (3), (1); wave number = 3R/4, not 3R.

Correct matching: P to 1,6; Q to 2,4; R to 2,5; S to 1,3. Answer: (C).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Spectrum
⏱ 2mℹ️ Source: QB

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