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Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructurePhotoelectric EffectEasy2 minPYQ_2023
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Values of work function (W0) for a few metals are given below

MetalLiNaKMgCuAg
W0eV2.422.32.253.74.84.3

The number of metals which will show photoelectric effect when light of wavelength 400 nm falls on it is _____

Given: h=6.6×1034 J s

c=3×108 ms1

e=1.6×1019 C

Answer:
3
Solution:

The minimum amount of energy necessary to start the emission of electrons from a metal's surface is known as its work function. The work function is the minimum amount of energy required to remove an electron from a metal's surface to infinity.

Energy of incident photon =hcλ

=6.6×10-34×3×108400×10-9 J

=6.6×10-34×3×108400×10-9×1.6×10-9 eV

=3.1 eV

If radiation energy is greater than work function of metal, then metal show photo electric effect.

 Li, Na and K will show photoelectric effect.

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Photoelectric Effect
2mℹ️ Source: PYQ_2023

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