Chemistry - Atomic Structure Question with Solution | TestHub

Maximum number of emission lines

 $$\begin{gathered} =\frac{\mathrm{\Delta n}\left(\mathrm{\Delta n}+1\right)}{2} \\ \mathrm{\Delta n}={\mathrm{n}}_2-{\mathrm{n}}_1 \\ {\mathrm{n}}_2=5 \\ {\mathrm{n}}_1=1 \end{gathered}$$

Maximum number of emission lines=$\frac{4\left(4+1\right)}{2}=\frac{20}{2}=10$

These lines correspond to the lyman series of the hydrogen spectrum