The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:
[Given: The threshold frequency of platinum is $1.3 \times 10^{15} s^{- 1}$ and $h = 6.6 \times 10^{- 34} Js$ ]

Question

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is:

[Given: The threshold frequency of platinum is $1.3 \times 10^{15} s^{- 1}$ and $h = 6.6 \times 10^{- 34} Js$ ]

TestHub · Accepted Answer

Radiation energy = threshold energy of metal + kinetic energy of ejected electron

For minimum energy,

Radiation energy = threshold energy of metal

$E = hν E = 6.6 \times 10^{- 34} \times 1.3 \times 10^{15} = 8.58 \times 10^{- 19} J$

Chemistry - Atomic Structure Question with Solution | TestHub