Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

The atomic masses of He and Ne are 4 and 20 a.m.u, respectively. The value of the de Broglie wavelength of He gas at − $73^{o} C$ is "M" times that of the de Broglie wavelength of Ne at $727^{o} C$ . M is

Answer:

5.00

Solution:

$λ \propto \frac{1}{\sqrt{M .T .}}$
$\frac{λ_{H e}}{λ_{N e}} = \sqrt{\frac{M_{N e} . T_{N e}}{M_{H e} . T_{H e}}} = \sqrt{\frac{20 \times 1000}{4 \times 200}} = 5$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...