Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureBohr's Atomic ModelMedium2 minPYQ_2019

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The ground state energy of a hydrogen atom is $- 13 .6 eV$ . The energy of second excited state of ${He}^{+}$ ion in $eV$ is:

Answer:

Solution:

$E = - 13 .6 (\frac{z^{2}}{n^{2}}) = - 13 .6 (\frac{2^{2}}{3^{2}}) = - 6 .04 eV$

(Second exited state $=$ Third shell, $n = 3$ )

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Bohr's Atomic Model

⏱ 2mℹ️ Source: PYQ_2019

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