Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

A certain metal when irradiated by light $(r = 3.2 \times 10^{16} H z)$ emtextts photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light $(r = 2.0 \times 10^{16} H z) .$ Then $v_{0}$ of metal is

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Answer:

Solution:

${(K E)}_{1} = h v_{1} - h v_{0}$

${(K E)}_{2} = h v_{2} - h v_{0}$

As, ${(K E)}_{1} = 2 \times {(K E)}_{2}$

$∴ h v_{1} - h v_{0} = 2 (h v_{2} - h v_{0})$

Or, $h v_{0} = 2 h v_{2} - h v_{1}$

Or , $v_{0} = 2 v_{1} - v_{1}$

$= 2 \times (2 \times 10^{16}) - (3.2 \times 10^{16})$

$= 0.8 \times 10^{16} H z = 8 \times 10^{15} H z$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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