Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

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The angular momentum of an electron in ${H e}^{+}$ moving in an orbit is $h / π$ . The de-brogile wavelength associated with electron is: [ $a_{0}$ is radius of first bohr's orbit of $H$ -atom]

Options:

Answer:

Solution:

$\frac{n h}{2 π} = \frac{h}{π}$
$n = 2$
$r = a_{0} \times \frac{n^{2}}{z} = a_{0} \times \frac{2^{2}}{2} = 2 a_{0}$
$n λ = 2 π r$
$λ = π r = π 2 a_{0}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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