Chemistry - Atomic Structure Question with Solution | TestHub

$\mathrm{\lambda }={\mathrm{c}}_2\left[\frac{{\mathrm{n}}^2}{{\mathrm{n}}^2-2^2}\right]$
or$\frac{1}{\mathrm{\lambda }}=\frac{1}{{\mathrm{c}}_2}\left[\frac{{\mathrm{n}}^2-2^2}{{\mathrm{n}}^2}\right]=\frac{1}{{\mathrm{c}}_2}\left[1-\frac{2^2}{{\mathrm{n}}^2}\right]$
$=\frac{2^2}{{\mathrm{c}}_2}\left[\frac{1}{2^2}-\frac{1}{{\mathrm{n}}^2}\right]$
So,${\mathrm{R}}_{\mathrm{H}}=\frac{2^2}{{\mathrm{c}}_2}$or${\mathrm{c}}_2=\frac{4}{{\mathrm{R}}_{\mathrm{H}}}$