An electron is accelerated from rest, by ' $V$ ' volts. Uncertainty in position ( $Δ x$ ) is plotted against minimum uncertainty in de-Broglie wavelength ( $Δ λ$ ) as following-
(de–Broglie wavelength for electron =
$(λ = \frac{150}{V} \overset{˚}{A})$

The value of 'V' is

Question

An electron is accelerated from rest, by ' $V$ ' volts. Uncertainty in position ( $Δ x$ ) is plotted against minimum uncertainty in de-Broglie wavelength ( $Δ λ$ ) as following-

(de–Broglie wavelength for electron =

$(λ = \frac{150}{V} \overset{˚}{A})$

The value of 'V' is

TestHub · Accepted Answer

( Δ x ⋅ Δ λ ≥ 4 π λ 2 ​ ) . Solution: ( Δ x = 4 π λ 2 ​ × Δ λ 1 ​ ) Y = mx from graph slope (m) = 1/2Π ( 4 π λ 2 ​ = 2 π 1 ​ ) λ 2 = 2 de- Broglie wavelength for electron λ = V 150 ​ A ˚ ​ v = 150 /λ 2 = 2 150 ​ =75V Final answer = 75

Chemistry - Atomic Structure Question with Solution | TestHub

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