Chemistry - Atomic Structure Question with Solution | TestHub
Match each orbital in Column I with the statements in Column II that are true for it (a Column I entry may match more than one Column II entry):
Column I (Orbital) | Column II (Statement) |
|---|---|
(P) 3s | (1) no radial node |
(Q) 3p | (2) one radial node |
(R) 4d | (3) two radial nodes |
(S) 4f | (4) one angular node |
| (5) two angular nodes |
| (6) total number of nodes = 2 |
Choose the option with the correct matching:
Options:
Answer:
Solution:
Radial nodes = , angular nodes = , total = .
(P) 3s: 2 radial, 0 angular, total 2 (3, 6).
(Q) 3p: 1 radial, 1 angular, total 2 (2, 4, 6).
(R) 4d: 1 radial, 2 angular, total 3 (2, 5).
(S) 4f: 0 radial, 3 angular, total 3 (1).
Correct matching: P to 3,6; Q to 2,4,6; R to 2,5; S to 1. Answer: (B).
