Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureSchrödinger's EquationMedium2 minQB
ChemistryMediummatching list

Match each orbital in Column I with the statements in Column II that are true for it (a Column I entry may match more than one Column II entry):

Column I (Orbital)

Column II (Statement)

(P) 3s

(1) no radial node

(Q) 3p

(2) one radial node

(R) 4d

(3) two radial nodes

(S) 4f

(4) one angular node

 

(5) two angular nodes

 

(6) total number of nodes = 2

Choose the option with the correct matching:

Options:

Answer:
B
Solution:

Radial nodes = , angular nodes = , total = .

(P) 3s: 2 radial, 0 angular, total 2 (3, 6).

(Q) 3p: 1 radial, 1 angular, total 2 (2, 4, 6).

(R) 4d: 1 radial, 2 angular, total 3 (2, 5).

(S) 4f: 0 radial, 3 angular, total 3 (1).

Correct matching: P to 3,6; Q to 2,4,6; R to 2,5; S to 1. Answer: (B).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Schrödinger's Equation
⏱ 2mℹ️ Source: QB

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