Chemistry - Atomic Structure Question with Solution | TestHub

We know
$\mathrm{r}=0.529\times \frac{{\mathrm{n}}^2}{\mathrm{Z}}\mathrm{Å}$
$\mathrm{r}={\mathrm{a}}_0\times \frac{{\mathrm{n}}^2}{\mathrm{Z}}$
$\mathrm{n}=2$
$\mathrm{Z}=3$
$\text{r}=\frac{{\text{a}}_{\text{0}}\times 4}{3}=\frac{4{\text{a}}_{\text{0}}}{3}$
Hence$\mathrm{x}=4,\mathrm{y}=3$
So, sum of$\mathrm{x}+\mathrm{y}=4+3=7$