An atom has a mass of 0.05 kg and the uncertainty in its velocity is 2.0 × 1 0 − 6 m/s. The uncertainty in its position is ( h = 6.626 × 1 0 − 34 Js)

Δ x = h / ( 4 πm Δ v ) = 6.626 × 1 0 − 34 / ( 4 × 3.14 × 0.05 × 2.0 × 1 0 − 6 ) = 6.626 × 1 0 − 34 / ( 1.257 × 1 0 − 6 ) = 5.27 × 1 0 − 28 m. 1 m = 100 cm, so this is 5.27 × 1 0 − 26 cm. Trap: option (A) has the right number with the wrong unit. Answer: (B).

Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureHeisensberg's Uncertainty PrincipleEasy2 minQB

ChemistryEasysingle choice

An atom has a mass of 0.05 kg and the uncertainty in its velocity is $2.0 \times 1 0^{- 6}$ m/s. The uncertainty in its position is ( $h = 6.626 \times 1 0^{- 34}$ Js)

Options:

Answer:

Solution:

$Δ x = h / (4 πm Δ v) = 6.626 \times 1 0^{- 34} / (4 \times 3.14 \times 0.05 \times 2.0 \times 1 0^{- 6}) = 6.626 \times 1 0^{- 34} / (1.257 \times 1 0^{- 6}) = 5.27 \times 1 0^{- 28}$ m.

1 m = 100 cm, so this is $5.27 \times 1 0^{- 26}$ cm.

Trap: option (A) has the right number with the wrong unit.

Answer: (B).

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Heisensberg's Uncertainty Principle

⏱ 2mℹ️ Source: QB

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