Chemistry - Atomic Structure Question with Solution | TestHub

Given that velocity of electron, $v=600 m/s$

Accuracy of velocity$=0.005\%$

According to Heisenberg's uncertainty principle

$\left(\mathrm{\Delta x}\right).\left(\mathrm{m\Delta v}\right)=\frac{\mathrm{h}}{4\mathrm{\pi }}$

$∆\mathrm{v}=0.005\%$ or $600 \mathrm{m} {\mathrm{s}}^{-1}$

$=\frac{600\times 0.005}{100}=0.03$

$∆\mathrm{x}\times 9.1\times {10}^{-31}\times 0.03=\frac{6.6\times {10}^{-34}}{4\times 3.14}$

Hence, $∆x=\frac{6.6\times {10}^{-34}}{4\times 3.14\times 0.03\times 9.1\times {10}^{-31}}$

$=1.92\times {10}^{-3} \mathrm{m}$