Chemistry - Atomic Structure Question with Solution | TestHub

The angular momentum of an electron in an${\mathrm{n}}^{\mathrm{t}\mathrm{h}}$orbit is given by
${\text{m}}_{\text{e}}\text{vr}=\text{n}\cdot \frac{\text{h}}{\text{2π}};\text{n}=\mathrm{1.2.3.......}$
$\mathrm{n}\frac{\mathrm{h}}{2\mathrm{\pi }}=14\frac{\mathrm{h}}{11}\Rightarrow \mathrm{n}=8$
$\mathrm{P}.\mathrm{E}=-2\times 13.6\frac{{\mathrm{Z}}^2}{{\mathrm{n}}^2}\mathrm{e}\mathrm{V}$
Potential energy$=-2\times 13.6\times {\left(\frac{\mathrm{Z}}{\mathrm{n}}\right)}^2$
Potential energy$=-2\times 13.6\times {\left(\frac{3}{8}\right)}^2$
$\because \mathrm{f}\mathrm{o}\mathrm{r}\mathrm{ }\mathrm{L}{\mathrm{i}}^{2+},\mathrm{Z}=3$