Chemistry - Atomic Structure Question with Solution | TestHub

I. $E=\frac{Z^2}{n^2}\times 13.6\mathrm{eV}....(i)$ or $\frac{I_1}{I_2}=\frac{Z_1^2}{n_1^2}\times \frac{n_2^2}{Z_2^2}....(ii)$ Given $I_1=-19.6\times 10^{-18},Z_1=2$, $n_1=1,Z_2=3$ and $n_2=1$ Substituting these values in equation (ii). $$-\frac{19.6\times 10^{-18}}{{\mathrm{I}}_2}=\frac{4}{1}\times \frac{1}{9}$$ or $I_2=-19.6\times 10^{-18}\times \frac{9}{4}$ $=-4.41\times 10^{-17}\mathrm{J}/$ atom