Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

$I E_{1}$ for H and He are 13.6 eV and 24.6 eV respectively. Thus, energy required in eV during the formation of ${He}^{2+}$ by

$He \to {He}^{2+} + {2e}^{-}$ is

Answer:

79.00

Solution:

$H \to H^{+} + e^{-}; 13 .6 eV$

${IE}_{2}$ of $He = 1 E_{1}$ of ${He}^{+} = E_{1 H} \times Z^{2} = 13 .6 \times 4$

$= 54 .4 eV$

${He}^{+} \to {He}^{2 +}; 54.4 eV$

So, $He \to {He}^{2+}; 54 .4 eV + 24 .6 eV$

$= 79.0 eV$

Stream:NTA_ABHYASSubject:ChemistryTopic:Atomic StructureSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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