Chemistry - Atomic Structure Question with Solution | TestHub

$\Delta x=0.1\mathring{A}=0.1\times 10^{-10}\mathrm{m}$ $m=9.11\times 10^{-31}\mathrm{kg}$ $h=6.626\times 10^{-34}\mathrm{Js}$ In uncertain position, $$\begin{array}{rl}& \Delta v\times \Delta x=\frac{h}{4\pi m}\\ & \Delta v\times 0.1\times 10^{-10}=\\ & \frac{6.626\times 10^{-34}}{4\times 3.14\times 9.11\times 10^{-31}}\\ & \Delta v=\\ & \frac{6.626\times 10^{-34}}{4\times 3.14\times 9.11\times 10^{-31}\times 0.1\times 10^{-10}}\\ & =5.785\times 10^6{\mathrm{ms}}^{-1}\\ & \end{array}$$