Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub
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Product is:
Options:
Answer:
Solution:
The reaction of pyridine with HNO₃ and H₂SO₄ is a nitration reaction. However, pyridine is much less reactive towards electrophilic aromatic substitution than benzene due to the electron-withdrawing nitrogen atom. Furthermore, pyridine is protonated in the presence of strong acids like H₂SO₄, forming the pyridinium ion, which is even MORE deactivated towards electrophilic substitution.
The nitration of pyridine requires harsh conditions (high temperatures and concentrated acids) and occurs at the 3-position.
Reaction:
Pyridine + HNO₃/H₂SO₄ -> 3-nitropyridine
Mechanism:
1. Protonation of pyridine:
Pyridine reacts with H₂SO₄ to form pyridinium ion.
2. Electrophilic attack:
The nitronium ion (NO₂⁺), generated from the reaction of HNO₃ and H₂SO₄, attacks the 3-position of the pyridinium ion. The 3-position is favored due to resonance stabilization of the intermediate and is less sterically hindered than the 2- or 4- positions.
3. Deprotonation:
Loss of a proton restores aromaticity, yielding 3-nitropyridine.
The product is shown in option A.