In compound C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular weight of compound is 108. Molecular formula of compound is

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Percentage R.N.A. Simplest ratio C 9 9 12 = 3 4 3 H 1 1 1 = 1 4 N 35 3.5 14 = 1 4 1 Empirical formula = C 3 H 4 N C 3 H 4 N n = 108 , 12 × 3 + 4 × 1 + 14 n = 108 54 n = 108 n = 108 54 = 2 So molecular formula = 2 × C 3 H 4 N = C 6 H 8 N 2

Chemistry - Aromatic Hydrocarbon Question with Solution | TestHub

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Doubts & Discussion

	Percentage	R.N.A.	Simplest ratio
C	9	$\frac{9}{12} = \frac{3}{4}$	3
H	1	$\frac{1}{1} = 1$	4
N	35	$\frac{3.5}{14} = \frac{1}{4}$	1