A plant that is heterozygous for two genes was selfed. A total of 1000 seeds were collected. Find out the total number of seeds heterozygous for the first gene and homozygous for the second gene.

Question

TestHub · Accepted Answer

The plant is heterozygous for two genes. Thus, its genotype is AaBb. Its selfing is actually a dihybrid cross.

The various genotypes of dihybrid cross are 1 AABB, 1 AAbb, 1 aabb, 1 aaBB, 2 AaBB, 2 AABb, 2 Aabb, 2 aaBb and 4 AaBb. Out of these AaBB and Aabb are the only two genotypes which are heterozygous for first gene and homozygous for second gene. Thus out of 16 possibilities 4 possibilities satisfy the given condition. Out of 1000 seeds the number of individuals will be $\frac{4}{16} \times 1000 = 250$

Zoology - Principles of Inheritance and Variation Question with Solution | TestHub

Options:

Doubts & Discussion