Zoology - Principles of Inheritance and Variation Question with Solution | TestHub

Two linked genes a and b show 20 % recombination, thus linkage is 80%.  The given phenotype of parents is ++/++ and ab/ab.

The parental genotype will be ++ and ab, while the recombinant type will be +a and +b.

Since % of recombination i.e. cross over frequency is 20%, the recombinant phenotype will be 10% each.

+a: 10%
+b: 10%

Similarly, since linkage is 80%, parental types will be 80% or 40% each for ++ and ab respectively.