Zoology - Evolution Question with Solution | TestHub

According to the Hardy-Weinberg principle,

Frequency of dominant allele$\left(\mathrm{A}\right)=\mathrm{p}$
Frequency of recessive allele$\left(\mathrm{a}\right)=\mathrm{q}$
Frequency of AA individuals$=\mathrm{p}\times \mathrm{p}={\mathrm{p}}^2$
Frequency of aa individuals$=\mathrm{ }\mathrm{q}\times \mathrm{q}={\mathrm{q}}^2$
Frequency of Aa individuals$=2\mathrm{p}\mathrm{q}$

Here q = 0.4
We know that,$\mathrm{p}+\mathrm{q}=1$, so the value of p comes out to be = 0.6
Total dominant phenotypes$=\mathrm{ }2\mathrm{p}\mathrm{q}+{\mathrm{p}}^2$
$= 2\times 0.6\times 0.4+0.6\times 0.6$
$=\mathrm{ }0.48+0.36=0.84$