Physics - Wave on String Question with Solution | TestHub

We have given, $y=0.03\sin (450t-9x)$ Comparing it with standard equation of wave, we get $\omega =$ $450\mathrm{k}=9$ $\therefore \mathrm{v}=\frac{\omega }{\mathrm{k}}=\frac{450}{9}=50\mathrm{m}/\mathrm{s}$ Velocity of travelling wave on a stretched string is given by $\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mu }}\Rightarrow \frac{\mathrm{T}}{\mu }=2500$ $\mu =$ linear mass density $\Rightarrow \mathrm{T}=2500\times 5\times 10^{-3}$ $\Rightarrow 12.5\mathrm{N}$