A system consists of two types of gas molecules A and B having same number density 2 × 1 0 25 / m 3 . The diameter of A and B are 10 A ˚ and 5 A ˚ respectively. They suffer collision at room temperature. The ratio of average distance covered by the molecule A to that of B between two successive collision is ____ × 1 0 − 2

λ = 2 π d 2 n 1 ⇒ λ B λ A = d A 2 d B 2 = ( 10 5 ) 2 . λ B λ A = 0.25 = 25 × 1 0 − 2 .

Start Free Mock LoginAlready registered? Login here

Physics - Thermodynamics Question with Solution | TestHub

PhysicsThermodynamicsMiscellaneousMedium3 minQB

PhysicsMediuminteger

A system consists of two types of gas molecules A and B having same number density $2 \times 1 0^{25} / m^{3}$ . The diameter of A and B are $10 \overset{˚}{A}$ and $5 \overset{˚}{A}$ respectively. They suffer collision at room temperature. The ratio of average distance covered by the molecule A to that of B between two successive collision is $____$ $\times 1 0^{- 2}$

Answer:

Solution:

$λ = \frac{1}{2 π d ^{2} n} \Rightarrow \frac{λ _{A}}{λ _{B}} = \frac{d _{B}^{2}}{d _{A}^{2}} = (\frac{5}{10})^{2}$ .

$\frac{λ _{A}}{λ _{B}} = 0.25 = 25 \times 1 0^{- 2}$ .

Stream:JEESubject:PhysicsTopic:ThermodynamicsSubtopic:Miscellaneous

⏱ 3mℹ️ Source: QB

Doubts & Discussion

Loading discussions...