Calculate θ 1 and θ 2 in shown situation and obtain 2 θ 1 + θ 2 (in °C).

Steady state: equal heat current through all three rods. ℓ K A ( 200 − θ 1 ) = ℓ 2 K A ( θ 1 − θ 2 ) = ℓ 1.5 K A ( θ 2 − 18 ) . Solving: θ 1 = 11 6 ∘ C , θ 2 = 7 4 ∘ C , so 2 θ 1 + θ 2 = 9 5 ∘ C .

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Physics - Thermodynamics Question with Solution | TestHub

PhysicsThermodynamicsMiscellaneousMedium3 minQB

PhysicsMediuminteger

Calculate $θ_{1}$ and $θ_{2}$ in shown situation and obtain $\frac{θ _{1} + θ _{2}}{2}$ (in °C).

diagram

Answer:

Solution:

Steady state: equal heat current through all three rods.

$\frac{K A ( 200 - θ _{1} )}{ℓ} = \frac{2 K A ( θ _{1} - θ _{2} )}{ℓ} = \frac{1.5 K A ( θ _{2} - 18 )}{ℓ}$ .

Solving: $θ_{1} = 11 6^{\circ} C, θ_{2} = 7 4^{\circ} C$ , so $\frac{θ _{1} + θ _{2}}{2} = 9 5^{\circ} C$ .

Stream:JEESubject:PhysicsTopic:ThermodynamicsSubtopic:Miscellaneous

⏱ 3mℹ️ Source: QB

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