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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesHard2 minQB

PhysicsHardnumerical

A gas of volume 800 $c m^{3}$ at 75 cm of mercury expands adiabatically to 1000 $c m^{3}$ and the pressure falls to 55 cm of mercury. Find the work done by the gas in joules (one decimal). Take 1 cm Hg = $1333.2$ Pa.

Answer:

17.10

Solution:

$γ = \frac{ln ( \frac{75}{55} )}{ln 1.25} = 1.390$ . $W = \frac{P _{1} V _{1} - P _{2} V _{2}}{γ - 1} = \frac{( 75 \times 800 - 55 \times 1000 ) \times 1.3332 \times 1 0 ^{- 3}}{0.390} = 17.1$ J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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